x^2-49x-12=0

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Solution for x^2-49x-12=0 equation:



x^2-49x-12=0
a = 1; b = -49; c = -12;
Δ = b2-4ac
Δ = -492-4·1·(-12)
Δ = 2449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-\sqrt{2449}}{2*1}=\frac{49-\sqrt{2449}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+\sqrt{2449}}{2*1}=\frac{49+\sqrt{2449}}{2} $

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